Nice Computer photos

A few nice Computer images I found:

Image from page 19 of “Trigonometria” (1658)
Computer
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Identifier: trigonometria00newt
Title: Trigonometria
Year: 1658 (1650s)
Authors: Newton, J.
Subjects:
Publisher:
Contributing Library: The Computer Museum Archive
Digitizing Sponsor: Gordon Bell

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Text Appearing Before Image:
C R, the fine of the fumme and dif-ference of the arches B A and ADequaltothere£tanglsmade of S P and D P, the fumme and difference of tfcfcfines, as was to be proved. Of the quantity of Right lines without the Circle. 24. The right lines without the Circle, whofe quantity we are to define, are fuch as touchthe circle, ana are called Tangents., 2<; The tangent of an arch is a right line perpendicular from the end of the diameter to theRadius continued through the term of that arch, of which it is the tangent- As in the annexed Dfctgram, the tangent H G is perpendicular from the end of the Diameter BAG, to the Radius A E continued through theterm of the arch E G unto H, agreeing both tothe arch E G, and to its complement to a Semi-circle BCE. 26 As the fine complement of an arch, is tothe fine thereof, To is Radius to the tangent ofthat arch. Deinonflratien. In this Diagram , the Triangles A E F andA H G are like,becaufe of their right angles atF and H, and their common angle at A.

Text Appearing After Image:
Theref3re, A G .»H G,the tangent of the arch E G, as was to be proved.Confettary, Therefore the fine and fine complement of an arch being given, the tangent and tangentcomplement of the fame arch is alfo given. For if A F be the fine of 49 degrees 1 and E F thefine of 41, H G (hall be the tangent of 4 t degrees; but if A F be 41 degrees, and EF 49, MGlhall be the tangent of 49 degrees, or the tangent complement of 41. 27 The Radius is a mean proportional between the tangent and the tangent complement ofan arch. Demonflration. In the preceding Diagram, let H G be the tangent of the arch E G, and CK.the tangent of the arch C E, or complement of E G ; the triangles A L H and A C K are like,becaufe of their right angles at L and C, and their cbmmo n angle at A. Therefore as A L, c-qual to H G, the tangent of the arch EG, is to L H equal to A G Radius: Co is A C Radius,to C K the tangent ot C E, or complement of the arch E G, as was to be proved. Confettary. Therefore the tangent of an ar

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Image from page 304 of “Pes Mechanicus Artificialis Uber Neu-Erfundener Was-stab” (1718)
Computer
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Identifier: pesmechanicusart00sche
Title: Pes Mechanicus Artificialis Uber Neu-Erfundener Was-stab
Year: 1718 (1710s)
Authors: Scheffelt, Michael
Subjects:
Publisher:
Contributing Library: The Computer Museum Archive
Digitizing Sponsor: Gordon Bell

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Text Appearing Before Image:
i SV- 3

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Note About Images
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Image from page 310 of “Pes Mechanicus Artificialis Uber Neu-Erfundener Was-stab” (1718)
Computer
Image by Internet Archive Book Images
Identifier: pesmechanicusart00sche
Title: Pes Mechanicus Artificialis Uber Neu-Erfundener Was-stab
Year: 1718 (1710s)
Authors: Scheffelt, Michael
Subjects:
Publisher:
Contributing Library: The Computer Museum Archive
Digitizing Sponsor: Gordon Bell

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About This Book: Catalog Entry
View All Images: All Images From Book

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Text Appearing Before Image:

Text Appearing After Image:
joj a

Note About Images
Please note that these images are extracted from scanned page images that may have been digitally enhanced for readability – coloration and appearance of these illustrations may not perfectly resemble the original work.